Base | Representation |
---|---|
bin | 100110101101011110111… |
… | …0110100100110110110101 |
3 | 200211121202200000201012001 |
4 | 1031122331312210312311 |
5 | 1144132041301304023 |
6 | 15152045345455301 |
7 | 1056245230615234 |
oct | 115327566446665 |
9 | 20747680021161 |
10 | 5320354713013 |
11 | 1771393596a2a |
12 | 71b154041531 |
13 | 2c7926c13c52 |
14 | 145713d46b1b |
15 | 935dbd666ad |
hex | 4d6bdda4db5 |
5320354713013 has 4 divisors (see below), whose sum is σ = 5551674483168. Its totient is φ = 5089034942860.
The previous prime is 5320354712999. The next prime is 5320354713041. The reversal of 5320354713013 is 3103174530235.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 5320354713013 - 233 = 5311764778421 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5320354713043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115659885043 + ... + 115659885088.
It is an arithmetic number, because the mean of its divisors is an integer number (1387918620792).
Almost surely, 25320354713013 is an apocalyptic number.
It is an amenable number.
5320354713013 is a deficient number, since it is larger than the sum of its proper divisors (231319770155).
5320354713013 is a wasteful number, since it uses less digits than its factorization.
5320354713013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 231319770154.
The product of its (nonzero) digits is 113400, while the sum is 37.
The spelling of 5320354713013 in words is "five trillion, three hundred twenty billion, three hundred fifty-four million, seven hundred thirteen thousand, thirteen".
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