Base | Representation |
---|---|
bin | 100110101101100001100… |
… | …0111110000110011110111 |
3 | 200211121222211100110111221 |
4 | 1031123003013300303313 |
5 | 1144132231413321003 |
6 | 15152102224211211 |
7 | 1056250353131332 |
oct | 115330307606367 |
9 | 20747884313457 |
10 | 5320443104503 |
11 | 177142947984a |
12 | 71b179769b07 |
13 | 2c793c3219c7 |
14 | 145721995619 |
15 | 935e49c67bd |
hex | 4d6c31f0cf7 |
5320443104503 has 2 divisors, whose sum is σ = 5320443104504. Its totient is φ = 5320443104502.
The previous prime is 5320443104461. The next prime is 5320443104563. The reversal of 5320443104503 is 3054013440235.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5320443104503 is a prime.
It is a super-2 number, since 2×53204431045032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5320443104563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2660221552251 + 2660221552252.
It is an arithmetic number, because the mean of its divisors is an integer number (2660221552252).
Almost surely, 25320443104503 is an apocalyptic number.
5320443104503 is a deficient number, since it is larger than the sum of its proper divisors (1).
5320443104503 is an equidigital number, since it uses as much as digits as its factorization.
5320443104503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 34.
Adding to 5320443104503 its reverse (3054013440235), we get a palindrome (8374456544738).
The spelling of 5320443104503 in words is "five trillion, three hundred twenty billion, four hundred forty-three million, one hundred four thousand, five hundred three".
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