53231044001 has 2 divisors, whose sum is σ = 53231044002. Its totient is φ = 53231044000.

The previous prime is 53231043997. The next prime is 53231044003. The reversal of 53231044001 is 10044013235.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52356304225 + 874739776 = 228815^2 + 29576^2 .

It is a cyclic number.

It is not a de Polignac number, because 53231044001 - 2² = 53231043997 is a prime.

Together with 53231044003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (53231044003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26615522000 + 26615522001.

It is an arithmetic number, because the mean of its divisors is an integer number (26615522001).

Almost surely, 2^53231044001 is an apocalyptic number.

It is an amenable number.

53231044001 is a deficient number, since it is larger than the sum of its proper divisors (1).

53231044001 is an equidigital number, since it uses as much as digits as its factorization.

53231044001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 53231044001 its reverse (10044013235), we get a palindrome (63275057236).

The spelling of 53231044001 in words is "fifty-three billion, two hundred thirty-one million, forty-four thousand, one".