Base | Representation |
---|---|
bin | 110001100100110100… |
… | …100010010100111001 |
3 | 12002101202201010021012 |
4 | 301210310202110321 |
5 | 1333004130214431 |
6 | 40242023123305 |
7 | 3563054615663 |
oct | 614464422471 |
9 | 162352633235 |
10 | 53231101241 |
11 | 2063662925a |
12 | a396ba3535 |
13 | 50342aa856 |
14 | 280d8d3533 |
15 | 15b838822b |
hex | c64d22539 |
53231101241 has 4 divisors (see below), whose sum is σ = 54469033872. Its totient is φ = 51993168612.
The previous prime is 53231101211. The next prime is 53231101249. The reversal of 53231101241 is 14210113235.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14210113235 = 5 ⋅2842022647.
It is a cyclic number.
It is not a de Polignac number, because 53231101241 - 218 = 53230839097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53231101249) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 618966251 + ... + 618966336.
It is an arithmetic number, because the mean of its divisors is an integer number (13617258468).
Almost surely, 253231101241 is an apocalyptic number.
It is an amenable number.
53231101241 is a deficient number, since it is larger than the sum of its proper divisors (1237932631).
53231101241 is a wasteful number, since it uses less digits than its factorization.
53231101241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1237932630.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 53231101241 its reverse (14210113235), we get a palindrome (67441214476).
The spelling of 53231101241 in words is "fifty-three billion, two hundred thirty-one million, one hundred one thousand, two hundred forty-one".
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