Base | Representation |
---|---|
bin | 100110101110111001101… |
… | …1001000111110101111111 |
3 | 200211220121221002221102222 |
4 | 1031131303121013311333 |
5 | 1144204311003222221 |
6 | 15153311510235555 |
7 | 1056413553122234 |
oct | 115356331076577 |
9 | 20756557087388 |
10 | 5323400445311 |
11 | 1772706852763 |
12 | 71b864055bbb |
13 | 2c7cc0c1b200 |
14 | 14592265578b |
15 | 937194409ab |
hex | 4d773647d7f |
5323400445311 has 12 divisors (see below), whose sum is σ = 5794259550768. Its totient is φ = 4888447409664.
The previous prime is 5323400445239. The next prime is 5323400445379. The reversal of 5323400445311 is 1135440043235.
It is not a de Polignac number, because 5323400445311 - 242 = 925353934207 is a prime.
It is a super-2 number, since 2×53234004453112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5323400445211) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 81572075 + ... + 81637308.
It is an arithmetic number, because the mean of its divisors is an integer number (482854962564).
Almost surely, 25323400445311 is an apocalyptic number.
5323400445311 is a deficient number, since it is larger than the sum of its proper divisors (470859105457).
5323400445311 is a wasteful number, since it uses less digits than its factorization.
5323400445311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 163209602 (or 163209589 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 5323400445311 its reverse (1135440043235), we get a palindrome (6458840488546).
The spelling of 5323400445311 in words is "five trillion, three hundred twenty-three billion, four hundred million, four hundred forty-five thousand, three hundred eleven".
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