Base | Representation |
---|---|
bin | 100110101110111101000… |
… | …1000000101110100101111 |
3 | 200211220220210200201002120 |
4 | 1031131322020011310233 |
5 | 1144210023413433403 |
6 | 15153331023524023 |
7 | 1056416424316563 |
oct | 115357210056457 |
9 | 20756823621076 |
10 | 5323513421103 |
11 | 17727645a7089 |
12 | 71b895a59613 |
13 | 2c800b455ba7 |
14 | 1459336636a3 |
15 | 93724309e53 |
hex | 4d77a205d2f |
5323513421103 has 4 divisors (see below), whose sum is σ = 7098017894808. Its totient is φ = 3549008947400.
The previous prime is 5323513421071. The next prime is 5323513421113. The reversal of 5323513421103 is 3011243153235.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5323513421103 - 25 = 5323513421071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5323513421113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 887252236848 + ... + 887252236853.
It is an arithmetic number, because the mean of its divisors is an integer number (1774504473702).
Almost surely, 25323513421103 is an apocalyptic number.
5323513421103 is a deficient number, since it is larger than the sum of its proper divisors (1774504473705).
5323513421103 is a wasteful number, since it uses less digits than its factorization.
5323513421103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1774504473704.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 5323513421103 its reverse (3011243153235), we get a palindrome (8334756574338).
The spelling of 5323513421103 in words is "five trillion, three hundred twenty-three billion, five hundred thirteen million, four hundred twenty-one thousand, one hundred three".
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