Base | Representation |
---|---|
bin | 110001100101011000… |
… | …000101111011111101 |
3 | 12002102102020200010201 |
4 | 301211120011323331 |
5 | 1333014022002031 |
6 | 40242555003501 |
7 | 3563230056424 |
oct | 614530057375 |
9 | 162372220121 |
10 | 53240422141 |
11 | 20640915185 |
12 | a39a139591 |
13 | 50361c228a |
14 | 2810c3c2bb |
15 | 15b90c9d61 |
hex | c65605efd |
53240422141 has 4 divisors (see below), whose sum is σ = 53559227232. Its totient is φ = 52921617052.
The previous prime is 53240422097. The next prime is 53240422159. The reversal of 53240422141 is 14122404235.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14122404235 = 5 ⋅2824480847.
It is a cyclic number.
It is not a de Polignac number, because 53240422141 - 213 = 53240413949 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53240422181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159402295 + ... + 159402628.
It is an arithmetic number, because the mean of its divisors is an integer number (13389806808).
Almost surely, 253240422141 is an apocalyptic number.
It is an amenable number.
53240422141 is a deficient number, since it is larger than the sum of its proper divisors (318805091).
53240422141 is a wasteful number, since it uses less digits than its factorization.
53240422141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 318805090.
The product of its (nonzero) digits is 7680, while the sum is 28.
Adding to 53240422141 its reverse (14122404235), we get a palindrome (67362826376).
The spelling of 53240422141 in words is "fifty-three billion, two hundred forty million, four hundred twenty-two thousand, one hundred forty-one".
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