Base | Representation |
---|---|
bin | 11000001101100110111010… |
… | …00000100110001100101111 |
3 | 20222112002101110000121012020 |
4 | 30012303131000212030233 |
5 | 23434322430331204130 |
6 | 305124002345441223 |
7 | 14133521664034626 |
oct | 1406633500461457 |
9 | 228462343017166 |
10 | 53244122522415 |
11 | 15a68784102120 |
12 | 5b7b098aa0213 |
13 | 2392b8c744076 |
14 | d2105a4b86bd |
15 | 6250061d7e10 |
hex | 306cdd02632f |
53244122522415 has 16 divisors (see below), whose sum is σ = 92935195675776. Its totient is φ = 25815332132000.
The previous prime is 53244122522359. The next prime is 53244122522431. The reversal of 53244122522415 is 51422522144235.
It is not a de Polignac number, because 53244122522415 - 26 = 53244122522351 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 161345825661 + ... + 161345825990.
It is an arithmetic number, because the mean of its divisors is an integer number (5808449729736).
Almost surely, 253244122522415 is an apocalyptic number.
53244122522415 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53244122522415 is a deficient number, since it is larger than the sum of its proper divisors (39691073153361).
53244122522415 is a wasteful number, since it uses less digits than its factorization.
53244122522415 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 322691651670.
The product of its digits is 768000, while the sum is 42.
The spelling of 53244122522415 in words is "fifty-three trillion, two hundred forty-four billion, one hundred twenty-two million, five hundred twenty-two thousand, four hundred fifteen".
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