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53282562917 is a prime number
BaseRepresentation
bin110001100111111000…
…110110001101100101
312002112100112122102012
4301213320312031211
51333110314003132
640251102124005
73564251212013
oct614770661545
9162470478365
1053282562917
1120662688171
12a3b0280605
135041b5834c
14281668b8b3
1515bcb510b2
hexc67e36365

53282562917 has 2 divisors, whose sum is σ = 53282562918. Its totient is φ = 53282562916.

The previous prime is 53282562913. The next prime is 53282562937. The reversal of 53282562917 is 71926528235.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51154678276 + 2127884641 = 226174^2 + 46129^2 .

It is a cyclic number.

It is not a de Polignac number, because 53282562917 - 22 = 53282562913 is a prime.

It is a super-3 number, since 3×532825629173 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53282562913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26641281458 + 26641281459.

It is an arithmetic number, because the mean of its divisors is an integer number (26641281459).

Almost surely, 253282562917 is an apocalyptic number.

It is an amenable number.

53282562917 is a deficient number, since it is larger than the sum of its proper divisors (1).

53282562917 is an equidigital number, since it uses as much as digits as its factorization.

53282562917 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1814400, while the sum is 50.

The spelling of 53282562917 in words is "fifty-three billion, two hundred eighty-two million, five hundred sixty-two thousand, nine hundred seventeen".