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53305144040 = 2357091879589
BaseRepresentation
bin110001101001001110…
…111111001011101000
312002120221000212220002
4301221032333023220
51333132104102130
640253230122132
73564644151131
oct615116771350
9162527025802
1053305144040
1120674400755
12a3b7950348
135046733565
142819688c88
1515beb11b45
hexc693bf2e8

53305144040 has 32 divisors (see below), whose sum is σ = 120105801000. Its totient is φ = 21291972864.

The previous prime is 53305144027. The next prime is 53305144111. The reversal of 53305144040 is 4044150335.

It can be written as a sum of positive squares in 4 ways, for example, as 31942983076 + 21362160964 = 178726^2 + 146158^2 .

It is a super-2 number, since 2×533051440402 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53305143994 and 53305144012.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 911435 + ... + 968154.

Almost surely, 253305144040 is an apocalyptic number.

It is an amenable number.

53305144040 is an abundant number, since it is smaller than the sum of its proper divisors (66800656960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53305144040 is a wasteful number, since it uses less digits than its factorization.

53305144040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1880309 (or 1880305 counting only the distinct ones).

The product of its (nonzero) digits is 14400, while the sum is 29.

Adding to 53305144040 its reverse (4044150335), we get a palindrome (57349294375).

The spelling of 53305144040 in words is "fifty-three billion, three hundred five million, one hundred forty-four thousand, forty".

Divisors: 1 2 4 5 8 10 20 40 709 1418 2836 3545 5672 7090 14180 28360 1879589 3759178 7518356 9397945 15036712 18795890 37591780 75183560 1332628601 2665257202 5330514404 6663143005 10661028808 13326286010 26652572020 53305144040