Base | Representation |
---|---|
bin | 110001101001100001… |
… | …101010110111111111 |
3 | 12002121021020201002011 |
4 | 301221201222313333 |
5 | 1333134332312344 |
6 | 40253523112051 |
7 | 3565033606543 |
oct | 615141526777 |
9 | 162537221064 |
10 | 53310041599 |
11 | 20677146321 |
12 | a3b9512627 |
13 | 5047759819 |
14 | 281a1a1a23 |
15 | 15c027cd34 |
hex | c6986adff |
53310041599 has 2 divisors, whose sum is σ = 53310041600. Its totient is φ = 53310041598.
The previous prime is 53310041569. The next prime is 53310041611. The reversal of 53310041599 is 99514001335.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53310041599 - 211 = 53310039551 is a prime.
It is a super-3 number, since 3×533100415993 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53310041569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26655020799 + 26655020800.
It is an arithmetic number, because the mean of its divisors is an integer number (26655020800).
Almost surely, 253310041599 is an apocalyptic number.
53310041599 is a deficient number, since it is larger than the sum of its proper divisors (1).
53310041599 is an equidigital number, since it uses as much as digits as its factorization.
53310041599 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72900, while the sum is 40.
The spelling of 53310041599 in words is "fifty-three billion, three hundred ten million, forty-one thousand, five hundred ninety-nine".
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