Base | Representation |
---|---|
bin | 110001101001100001… |
… | …101010111000001011 |
3 | 12002121021020201002121 |
4 | 301221201222320023 |
5 | 1333134332312421 |
6 | 40253523112111 |
7 | 3565033606561 |
oct | 615141527013 |
9 | 162537221077 |
10 | 53310041611 |
11 | 20677146332 |
12 | a3b9512637 |
13 | 5047759828 |
14 | 281a1a1a31 |
15 | 15c027cd41 |
hex | c6986ae0b |
53310041611 has 2 divisors, whose sum is σ = 53310041612. Its totient is φ = 53310041610.
The previous prime is 53310041599. The next prime is 53310041663. The reversal of 53310041611 is 11614001335.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53310041611 is a prime.
It is not a weakly prime, because it can be changed into another prime (53310041011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26655020805 + 26655020806.
It is an arithmetic number, because the mean of its divisors is an integer number (26655020806).
Almost surely, 253310041611 is an apocalyptic number.
53310041611 is a deficient number, since it is larger than the sum of its proper divisors (1).
53310041611 is an equidigital number, since it uses as much as digits as its factorization.
53310041611 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 53310041611 its reverse (11614001335), we get a palindrome (64924042946).
It can be divided in two parts, 53 and 310041611, that added together give a square (310041664 = 176082).
The spelling of 53310041611 in words is "fifty-three billion, three hundred ten million, forty-one thousand, six hundred eleven".
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