53311311311335 has 32 divisors (see below), whose sum is σ = 79790675673600. Its totient is φ = 33219935602560.

The previous prime is 53311311311263. The next prime is 53311311311341.

53311311311335 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 53311311311335 - 2¹³ = 53311311303143 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53311311311335.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 26291280 + ... + 28246309.

It is an arithmetic number, because the mean of its divisors is an integer number (2493458614800).

Almost surely, 2^{53311311311335} is an apocalyptic number.

53311311311335 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

53311311311335 is a deficient number, since it is larger than the sum of its proper divisors (26479364362265).

53311311311335 is a wasteful number, since it uses less digits than its factorization.

53311311311335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54540151.

The product of its digits is 18225, while the sum is 34.

It can be divided in two parts, 5331131 and 1311335, that added together give a palindrome (6642466).

The spelling of 53311311311335 in words is "fifty-three trillion, three hundred eleven billion, three hundred eleven million, three hundred eleven thousand, three hundred thirty-five".