Base | Representation |
---|---|
bin | 100110110010111111111… |
… | …1001100100101000110111 |
3 | 200212202100012102110102112 |
4 | 1031211333321210220313 |
5 | 1144330321223304142 |
6 | 15201325020001235 |
7 | 1060144614660611 |
oct | 115457771445067 |
9 | 20782305373375 |
10 | 5332200213047 |
11 | 1776412012484 |
12 | 7214bb09021b |
13 | 2c8a94062576 |
14 | 146119227db1 |
15 | 93a81c69382 |
hex | 4d97fe64a37 |
5332200213047 has 2 divisors, whose sum is σ = 5332200213048. Its totient is φ = 5332200213046.
The previous prime is 5332200213029. The next prime is 5332200213089. The reversal of 5332200213047 is 7403120022335.
It is a happy number.
5332200213047 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5332200213047 - 216 = 5332200147511 is a prime.
It is a super-2 number, since 2×53322002130472 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5332200210047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2666100106523 + 2666100106524.
It is an arithmetic number, because the mean of its divisors is an integer number (2666100106524).
Almost surely, 25332200213047 is an apocalyptic number.
5332200213047 is a deficient number, since it is larger than the sum of its proper divisors (1).
5332200213047 is an equidigital number, since it uses as much as digits as its factorization.
5332200213047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240, while the sum is 32.
The spelling of 5332200213047 in words is "five trillion, three hundred thirty-two billion, two hundred million, two hundred thirteen thousand, forty-seven".
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