Base | Representation |
---|---|
bin | 1111100001001111010… |
… | …00111111100010010011 |
3 | 1212222101111000120201121 |
4 | 13300213220333202103 |
5 | 32214034144032011 |
6 | 1044544553143111 |
7 | 53345131506115 |
oct | 7604750774223 |
9 | 1788344016647 |
10 | 533241002131 |
11 | 19616770a392 |
12 | 874193baa97 |
13 | 3b390b093c6 |
14 | 1bb47c8b3b5 |
15 | dd0e058e71 |
hex | 7c27a3f893 |
533241002131 has 32 divisors (see below), whose sum is σ = 565707276288. Its totient is φ = 501637113120.
The previous prime is 533241002111. The next prime is 533241002159. The reversal of 533241002131 is 131200142335.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 533241002131 - 29 = 533241001619 is a prime.
It is a super-2 number, since 2×5332410021312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 533241002096 and 533241002105.
It is not an unprimeable number, because it can be changed into a prime (533241002111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 192713110 + ... + 192715876.
It is an arithmetic number, because the mean of its divisors is an integer number (17678352384).
Almost surely, 2533241002131 is an apocalyptic number.
533241002131 is a deficient number, since it is larger than the sum of its proper divisors (32466274157).
533241002131 is a wasteful number, since it uses less digits than its factorization.
533241002131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3471.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 533241002131 its reverse (131200142335), we get a palindrome (664441144466).
The spelling of 533241002131 in words is "five hundred thirty-three billion, two hundred forty-one million, two thousand, one hundred thirty-one".
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