Base | Representation |
---|---|
bin | 11000010000011001100011… |
… | …00011110111000011100101 |
3 | 20222212020221102111012002211 |
4 | 30020030301203313003211 |
5 | 23442410340231130112 |
6 | 305240023251003421 |
7 | 14143455451005331 |
oct | 1410146143670345 |
9 | 228766842435084 |
10 | 53340030333157 |
11 | 15aa541a607927 |
12 | 5b957a4299571 |
13 | 239bc354c4839 |
14 | d25957c687c1 |
15 | 62776b03c0a7 |
hex | 3083318f70e5 |
53340030333157 has 2 divisors, whose sum is σ = 53340030333158. Its totient is φ = 53340030333156.
The previous prime is 53340030333103. The next prime is 53340030333253. The reversal of 53340030333157 is 75133303004335.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 37711402003521 + 15628628329636 = 6140961^2 + 3953306^2 .
It is a cyclic number.
It is not a de Polignac number, because 53340030333157 - 231 = 53337882849509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53340030333757) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26670015166578 + 26670015166579.
It is an arithmetic number, because the mean of its divisors is an integer number (26670015166579).
Almost surely, 253340030333157 is an apocalyptic number.
It is an amenable number.
53340030333157 is a deficient number, since it is larger than the sum of its proper divisors (1).
53340030333157 is an equidigital number, since it uses as much as digits as its factorization.
53340030333157 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 510300, while the sum is 40.
The spelling of 53340030333157 in words is "fifty-three trillion, three hundred forty billion, thirty million, three hundred thirty-three thousand, one hundred fifty-seven".
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