Base | Representation |
---|---|
bin | 11000010000011001100011… |
… | …00011110111000010101111 |
3 | 20222212020221102111012000211 |
4 | 30020030301203313002233 |
5 | 23442410340231124403 |
6 | 305240023251003251 |
7 | 14143455451005223 |
oct | 1410146143670257 |
9 | 228766842435024 |
10 | 53340030333103 |
11 | 15aa541a607888 |
12 | 5b957a4299527 |
13 | 239bc354c47c7 |
14 | d25957c68783 |
15 | 62776b03c06d |
hex | 3083318f70af |
53340030333103 has 2 divisors, whose sum is σ = 53340030333104. Its totient is φ = 53340030333102.
The previous prime is 53340030333101. The next prime is 53340030333157. The reversal of 53340030333103 is 30133303004335.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53340030333103 - 21 = 53340030333101 is a prime.
Together with 53340030333101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53340030333101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26670015166551 + 26670015166552.
It is an arithmetic number, because the mean of its divisors is an integer number (26670015166552).
Almost surely, 253340030333103 is an apocalyptic number.
53340030333103 is a deficient number, since it is larger than the sum of its proper divisors (1).
53340030333103 is an equidigital number, since it uses as much as digits as its factorization.
53340030333103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43740, while the sum is 31.
Adding to 53340030333103 its reverse (30133303004335), we get a palindrome (83473333337438).
The spelling of 53340030333103 in words is "fifty-three trillion, three hundred forty billion, thirty million, three hundred thirty-three thousand, one hundred three".
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