Base | Representation |
---|---|
bin | 11000010000011011111011… |
… | …11010011010100110011111 |
3 | 20222212101020200212202221011 |
4 | 30020031331322122212133 |
5 | 23442421001144024320 |
6 | 305240354330520051 |
7 | 14143532264114332 |
oct | 1410157572324637 |
9 | 228771220782834 |
10 | 53341311314335 |
11 | 15aa5a176a4a60 |
12 | 5b95aa1296027 |
13 | 239c0aaa00b75 |
14 | d25a3a038619 |
15 | 6277e372205a |
hex | 30837de9a99f |
53341311314335 has 32 divisors (see below), whose sum is σ = 69867583948800. Its totient is φ = 38772041702400.
The previous prime is 53341311314251. The next prime is 53341311314383.
53341311314335 is nontrivially palindromic in base 10.
It is a de Polignac number, because none of the positive numbers 2k-53341311314335 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1350017230 + ... + 1350056740.
It is an arithmetic number, because the mean of its divisors is an integer number (2183361998400).
Almost surely, 253341311314335 is an apocalyptic number.
53341311314335 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53341311314335 is a deficient number, since it is larger than the sum of its proper divisors (16526272634465).
53341311314335 is a wasteful number, since it uses less digits than its factorization.
53341311314335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52599.
The product of its digits is 291600, while the sum is 40.
It can be divided in two parts, 5334131 and 1314335, that added together give a palindrome (6648466).
The spelling of 53341311314335 in words is "fifty-three trillion, three hundred forty-one billion, three hundred eleven million, three hundred fourteen thousand, three hundred thirty-five".
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