Base | Representation |
---|---|
bin | 110001101011011100… |
… | …000011100100101111 |
3 | 12002200111121200022122 |
4 | 301223130003210233 |
5 | 1333221040434320 |
6 | 40301030503155 |
7 | 3565603401323 |
oct | 615334034457 |
9 | 162614550278 |
10 | 53342124335 |
11 | 20693269585 |
12 | a408204abb |
13 | 50512b07a6 |
14 | 2820553983 |
15 | 15c2eb8d25 |
hex | c6b70392f |
53342124335 has 4 divisors (see below), whose sum is σ = 64010549208. Its totient is φ = 42673699464.
The previous prime is 53342124301. The next prime is 53342124373.
53342124335 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53342124335 - 26 = 53342124271 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53342124295 and 53342124304.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5334212429 + ... + 5334212438.
It is an arithmetic number, because the mean of its divisors is an integer number (16002637302).
Almost surely, 253342124335 is an apocalyptic number.
53342124335 is a deficient number, since it is larger than the sum of its proper divisors (10668424873).
53342124335 is a wasteful number, since it uses less digits than its factorization.
53342124335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10668424872.
The product of its digits is 129600, while the sum is 35.
The spelling of 53342124335 in words is "fifty-three billion, three hundred forty-two million, one hundred twenty-four thousand, three hundred thirty-five".
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