Base | Representation |
---|---|
bin | 100110110100000001111… |
… | …0110100101010101110011 |
3 | 200212222001111002121101211 |
4 | 1031220003312211111303 |
5 | 1144344334442201003 |
6 | 15202332421340551 |
7 | 1060253516022253 |
oct | 115500366452563 |
9 | 20788044077354 |
10 | 5334414022003 |
11 | 1777348713960 |
12 | 721a18567757 |
13 | 2c90578ba3b1 |
14 | 14628925b963 |
15 | 93b612b296d |
hex | 4da03da5573 |
5334414022003 has 8 divisors (see below), whose sum is σ = 6125642896320. Its totient is φ = 4594232171880.
The previous prime is 5334414021983. The next prime is 5334414022013. The reversal of 5334414022003 is 3002204144335.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5334414022003 - 221 = 5334411924851 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5334414022013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12761755825 + ... + 12761756242.
It is an arithmetic number, because the mean of its divisors is an integer number (765705362040).
Almost surely, 25334414022003 is an apocalyptic number.
5334414022003 is a deficient number, since it is larger than the sum of its proper divisors (791228874317).
5334414022003 is a wasteful number, since it uses less digits than its factorization.
5334414022003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25523512097.
The product of its (nonzero) digits is 34560, while the sum is 31.
Adding to 5334414022003 its reverse (3002204144335), we get a palindrome (8336618166338).
The spelling of 5334414022003 in words is "five trillion, three hundred thirty-four billion, four hundred fourteen million, twenty-two thousand, three".
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