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533511212140 = 22526675560607
BaseRepresentation
bin1111100001101111011…
…11110000110001101100
31220000002022110200011201
413300313233300301230
532220112332242030
61045031444455244
753354622323314
oct7606757606154
91800068420151
10533511212140
11196296197145
12874939aa524
133b404aa699a
141bb71b08444
15dd27b312ca
hex7c37bf0c6c

533511212140 has 12 divisors (see below), whose sum is σ = 1120373545536. Its totient is φ = 213404484848.

The previous prime is 533511212099. The next prime is 533511212153. The reversal of 533511212140 is 41212115335.

It is a junction number, because it is equal to n+sod(n) for n = 533511212099 and 533511212108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13337780284 + ... + 13337780323.

It is an arithmetic number, because the mean of its divisors is an integer number (93364462128).

Almost surely, 2533511212140 is an apocalyptic number.

It is an amenable number.

533511212140 is an abundant number, since it is smaller than the sum of its proper divisors (586862333396).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

533511212140 is a wasteful number, since it uses less digits than its factorization.

533511212140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26675560616 (or 26675560614 counting only the distinct ones).

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 533511212140 its reverse (41212115335), we get a palindrome (574723327475).

The spelling of 533511212140 in words is "five hundred thirty-three billion, five hundred eleven million, two hundred twelve thousand, one hundred forty".

Divisors: 1 2 4 5 10 20 26675560607 53351121214 106702242428 133377803035 266755606070 533511212140