Base | Representation |
---|---|
bin | 100110110100010111111… |
… | …0011100101011001011001 |
3 | 200220000221212122222112112 |
4 | 1031220233303211121121 |
5 | 1144402342231331210 |
6 | 15202533522522105 |
7 | 1060311011640401 |
oct | 115505763453131 |
9 | 20800855588475 |
10 | 5335151433305 |
11 | 1777696995991 |
12 | 721ba3506335 |
13 | 2c91445c7c45 |
14 | 146319173801 |
15 | 93ba5dc4d05 |
hex | 4da2fce5659 |
5335151433305 has 8 divisors (see below), whose sum is σ = 6418639773000. Its totient is φ = 4257149111296.
The previous prime is 5335151433281. The next prime is 5335151433319. The reversal of 5335151433305 is 5033341515335.
It can be written as a sum of positive squares in 4 ways, for example, as 82057039936 + 5253094393369 = 286456^2 + 2291963^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5335151433305 - 214 = 5335151416921 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1371502280 + ... + 1371506169.
It is an arithmetic number, because the mean of its divisors is an integer number (802329971625).
Almost surely, 25335151433305 is an apocalyptic number.
It is an amenable number.
5335151433305 is a deficient number, since it is larger than the sum of its proper divisors (1083488339695).
5335151433305 is a wasteful number, since it uses less digits than its factorization.
5335151433305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2743008843.
The product of its (nonzero) digits is 607500, while the sum is 41.
The spelling of 5335151433305 in words is "five trillion, three hundred thirty-five billion, one hundred fifty-one million, four hundred thirty-three thousand, three hundred five".
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