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5335151433305 = 53892743008449
BaseRepresentation
bin100110110100010111111…
…0011100101011001011001
3200220000221212122222112112
41031220233303211121121
51144402342231331210
615202533522522105
71060311011640401
oct115505763453131
920800855588475
105335151433305
111777696995991
12721ba3506335
132c91445c7c45
14146319173801
1593ba5dc4d05
hex4da2fce5659

5335151433305 has 8 divisors (see below), whose sum is σ = 6418639773000. Its totient is φ = 4257149111296.

The previous prime is 5335151433281. The next prime is 5335151433319. The reversal of 5335151433305 is 5033341515335.

It can be written as a sum of positive squares in 4 ways, for example, as 82057039936 + 5253094393369 = 286456^2 + 2291963^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5335151433305 - 214 = 5335151416921 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1371502280 + ... + 1371506169.

It is an arithmetic number, because the mean of its divisors is an integer number (802329971625).

Almost surely, 25335151433305 is an apocalyptic number.

It is an amenable number.

5335151433305 is a deficient number, since it is larger than the sum of its proper divisors (1083488339695).

5335151433305 is a wasteful number, since it uses less digits than its factorization.

5335151433305 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2743008843.

The product of its (nonzero) digits is 607500, while the sum is 41.

The spelling of 5335151433305 in words is "five trillion, three hundred thirty-five billion, one hundred fifty-one million, four hundred thirty-three thousand, three hundred five".

Divisors: 1 5 389 1945 2743008449 13715042245 1067030286661 5335151433305