53352340493 has 2 divisors, whose sum is σ = 53352340494. Its totient is φ = 53352340492.

The previous prime is 53352340487. The next prime is 53352340501. The reversal of 53352340493 is 39404325335.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 44000096644 + 9352243849 = 209762^2 + 96707^2 .

It is a cyclic number.

It is not a de Polignac number, because 53352340493 - 2¹⁸ = 53352078349 is a prime.

It is a super-3 number, since 3×53352340493³ (a number of 33 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 53352340493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53352340403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26676170246 + 26676170247.

It is an arithmetic number, because the mean of its divisors is an integer number (26676170247).

Almost surely, 2^53352340493 is an apocalyptic number.

It is an amenable number.

53352340493 is a deficient number, since it is larger than the sum of its proper divisors (1).

53352340493 is an equidigital number, since it uses as much as digits as its factorization.

53352340493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 583200, while the sum is 41.

The spelling of 53352340493 in words is "fifty-three billion, three hundred fifty-two million, three hundred forty thousand, four hundred ninety-three".