Base | Representation |
---|---|
bin | 1100101110000… |
… | …1110001000101 |
3 | 10201101122022002 |
4 | 3023201301011 |
5 | 102124303131 |
6 | 5143315045 |
7 | 1215332453 |
oct | 313416105 |
9 | 121348262 |
10 | 53353541 |
11 | 2813133a |
12 | 15a4ba85 |
13 | b090957 |
14 | 712b9d3 |
15 | 4a3d6cb |
hex | 32e1c45 |
53353541 has 2 divisors, whose sum is σ = 53353542. Its totient is φ = 53353540.
The previous prime is 53353481. The next prime is 53353543. The reversal of 53353541 is 14535335.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28890625 + 24462916 = 5375^2 + 4946^2 .
It is a cyclic number.
It is not a de Polignac number, because 53353541 - 26 = 53353477 is a prime.
It is a super-3 number, since 3×533535413 (a number of 24 digits) contains 333 as substring.
Together with 53353543, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53353543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26676770 + 26676771.
It is an arithmetic number, because the mean of its divisors is an integer number (26676771).
Almost surely, 253353541 is an apocalyptic number.
It is an amenable number.
53353541 is a deficient number, since it is larger than the sum of its proper divisors (1).
53353541 is an equidigital number, since it uses as much as digits as its factorization.
53353541 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13500, while the sum is 29.
The square root of 53353541 is about 7304.3508267333. The cubic root of 53353541 is about 376.4619459054.
Adding to 53353541 its reverse (14535335), we get a palindrome (67888876).
The spelling of 53353541 in words is "fifty-three million, three hundred fifty-three thousand, five hundred forty-one".
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