Base | Representation |
---|---|
bin | 100110110100100000100… |
… | …1111110010101011010101 |
3 | 200220001201021020222000112 |
4 | 1031221001033302223111 |
5 | 1144403442133243110 |
6 | 15203022534252405 |
7 | 1060321164026333 |
oct | 115510117625325 |
9 | 20801637228015 |
10 | 5335444040405 |
11 | 177782707aa36 |
12 | 7220654b7105 |
13 | 2c9190107a3b |
14 | 146345d80b53 |
15 | 93bc1923405 |
hex | 4da413f2ad5 |
5335444040405 has 4 divisors (see below), whose sum is σ = 6402532848492. Its totient is φ = 4268355232320.
The previous prime is 5335444040383. The next prime is 5335444040417. The reversal of 5335444040405 is 5040404445335.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3849283117681 + 1486160922724 = 1961959^2 + 1219082^2 .
It is a de Polignac number, because none of the positive numbers 2k-5335444040405 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 533544404036 + ... + 533544404045.
It is an arithmetic number, because the mean of its divisors is an integer number (1600633212123).
Almost surely, 25335444040405 is an apocalyptic number.
It is an amenable number.
5335444040405 is a deficient number, since it is larger than the sum of its proper divisors (1067088808087).
5335444040405 is a wasteful number, since it uses less digits than its factorization.
5335444040405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1067088808086.
The product of its (nonzero) digits is 1152000, while the sum is 41.
The spelling of 5335444040405 in words is "five trillion, three hundred thirty-five billion, four hundred forty-four million, forty thousand, four hundred five".
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