Base | Representation |
---|---|
bin | 100110110100100000100… |
… | …1111110010101101010011 |
3 | 200220001201021020222012012 |
4 | 1031221001033302231103 |
5 | 1144403442133244111 |
6 | 15203022534253135 |
7 | 1060321164026603 |
oct | 115510117625523 |
9 | 20801637228165 |
10 | 5335444040531 |
11 | 1777827080040 |
12 | 7220654b71ab |
13 | 2c9190107b07 |
14 | 146345d80c03 |
15 | 93bc192348b |
hex | 4da413f2b53 |
5335444040531 has 16 divisors (see below), whose sum is σ = 6164116223328. Its totient is φ = 4564159603200.
The previous prime is 5335444040483. The next prime is 5335444040551. The reversal of 5335444040531 is 1350404445335.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 5335444040531 - 210 = 5335444039507 is a prime.
It is a super-2 number, since 2×53354440405312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5335444040551) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1969460 + ... + 3814401.
It is an arithmetic number, because the mean of its divisors is an integer number (385257263958).
Almost surely, 25335444040531 is an apocalyptic number.
5335444040531 is a deficient number, since it is larger than the sum of its proper divisors (828672182797).
5335444040531 is a wasteful number, since it uses less digits than its factorization.
5335444040531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5788822.
The product of its (nonzero) digits is 864000, while the sum is 41.
Adding to 5335444040531 its reverse (1350404445335), we get a palindrome (6685848485866).
The spelling of 5335444040531 in words is "five trillion, three hundred thirty-five billion, four hundred forty-four million, forty thousand, five hundred thirty-one".
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