53365312000445 has 4 divisors (see below), whose sum is σ = 64038374400540. Its totient is φ = 42692249600352.

The previous prime is 53365312000439. The next prime is 53365312000487. The reversal of 53365312000445 is 54400021356335.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 18531070581529 + 34834241418916 = 4304773^2 + 5902054^2 .

It is a cyclic number.

It is not a de Polignac number, because 53365312000445 - 2¹⁰ = 53365311999421 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5336531200040 + ... + 5336531200049.

It is an arithmetic number, because the mean of its divisors is an integer number (16009593600135).

Almost surely, 2^{53365312000445} is an apocalyptic number.

It is an amenable number.

53365312000445 is a deficient number, since it is larger than the sum of its proper divisors (10673062400095).

53365312000445 is a wasteful number, since it uses less digits than its factorization.

53365312000445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10673062400094.

The product of its (nonzero) digits is 648000, while the sum is 41.

The spelling of 53365312000445 in words is "fifty-three trillion, three hundred sixty-five billion, three hundred twelve million, four hundred forty-five", and thus it is an aban number.