Base | Representation |
---|---|
bin | 11000010001110001101101… |
… | …11011110110010001111111 |
3 | 21000000210010021021220200222 |
4 | 30020320312323312101333 |
5 | 23444144310434212100 |
6 | 305313452244211555 |
7 | 14150052451205321 |
oct | 1410706673662177 |
9 | 230023107256628 |
10 | 53387365147775 |
11 | 160134aa90272a |
12 | 5ba29b4699bbb |
13 | 23a353a04a399 |
14 | d27d68629611 |
15 | 628adb927485 |
hex | 308e36ef647f |
53387365147775 has 24 divisors (see below), whose sum is σ = 67332695751600. Its totient is φ = 41979557376000.
The previous prime is 53387365147757. The next prime is 53387365147799. The reversal of 53387365147775 is 57774156378335.
It is a de Polignac number, because none of the positive numbers 2k-53387365147775 is a prime.
It is a Smith number, since the sum of its digits (71) coincides with the sum of the digits of its prime factors.
It is a junction number, because it is equal to n+sod(n) for n = 53387365147699 and 53387365147708.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6858425 + ... + 12402125.
It is an arithmetic number, because the mean of its divisors is an integer number (2805528989650).
Almost surely, 253387365147775 is an apocalyptic number.
53387365147775 is a deficient number, since it is larger than the sum of its proper divisors (13945330603825).
53387365147775 is a wasteful number, since it uses less digits than its factorization.
53387365147775 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5550299 (or 5550294 counting only the distinct ones).
The product of its digits is 1555848000, while the sum is 71.
The spelling of 53387365147775 in words is "fifty-three trillion, three hundred eighty-seven billion, three hundred sixty-five million, one hundred forty-seven thousand, seven hundred seventy-five".
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