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53400115 = 510680023
BaseRepresentation
bin1100101110110…
…1001000110011
310201111000012001
43023231020303
5102132300430
65144314431
71215615316
oct313551063
9121430161
1053400115
112816332a
1215a72a17
13b0a8c02
14714097d
154a4c3ca
hex32ed233

53400115 has 4 divisors (see below), whose sum is σ = 64080144. Its totient is φ = 42720088.

The previous prime is 53400103. The next prime is 53400121. The reversal of 53400115 is 51100435.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53400115 - 223 = 45011507 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53400092 and 53400101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5340007 + ... + 5340016.

It is an arithmetic number, because the mean of its divisors is an integer number (16020036).

Almost surely, 253400115 is an apocalyptic number.

53400115 is a deficient number, since it is larger than the sum of its proper divisors (10680029).

53400115 is a wasteful number, since it uses less digits than its factorization.

53400115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10680028.

The product of its (nonzero) digits is 300, while the sum is 19.

The square root of 53400115 is about 7307.5382311692. The cubic root of 53400115 is about 376.5714559086.

The spelling of 53400115 in words is "fifty-three million, four hundred thousand, one hundred fifteen".

Divisors: 1 5 10680023 53400115