Base | Representation |
---|---|
bin | 100110110110101001010… |
… | …1111011010110010100101 |
3 | 200220111120001021102120010 |
4 | 1031231102233122302211 |
5 | 1144442341310324031 |
6 | 15205102125200433 |
7 | 1060542661263126 |
oct | 115552257326245 |
9 | 20814501242503 |
10 | 5340032511141 |
11 | 1779771157a09 |
12 | 722b26100119 |
13 | 2c9741919393 |
14 | 14665d51a04d |
15 | 93d8e68a246 |
hex | 4db52bdaca5 |
5340032511141 has 12 divisors (see below), whose sum is σ = 7274756838752. Its totient is φ = 3484276527768.
The previous prime is 5340032511131. The next prime is 5340032511239. The reversal of 5340032511141 is 1411152300435.
It is not a de Polignac number, because 5340032511141 - 211 = 5340032509093 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5340032511099 and 5340032511108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5340032511131) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 402893065 + ... + 402906318.
Almost surely, 25340032511141 is an apocalyptic number.
It is an amenable number.
5340032511141 is a deficient number, since it is larger than the sum of its proper divisors (1934724327611).
5340032511141 is an equidigital number, since it uses as much as digits as its factorization.
5340032511141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 805799480 (or 805799433 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 5340032511141 its reverse (1411152300435), we get a palindrome (6751184811576).
The spelling of 5340032511141 in words is "five trillion, three hundred forty billion, thirty-two million, five hundred eleven thousand, one hundred forty-one".
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