Base | Representation |
---|---|
bin | 100110110110101110010… |
… | …1100001000011111111111 |
3 | 200220111222200100101010222 |
4 | 1031231130230020133333 |
5 | 1144443212023000301 |
6 | 15205130450451555 |
7 | 1060550056064432 |
oct | 115553454103777 |
9 | 20814880311128 |
10 | 5340199421951 |
11 | 177984739a529 |
12 | 722b71b93bbb |
13 | 2c976a389584 |
14 | 146677767819 |
15 | 93d9e15a31b |
hex | 4db5cb087ff |
5340199421951 has 2 divisors, whose sum is σ = 5340199421952. Its totient is φ = 5340199421950.
The previous prime is 5340199421717. The next prime is 5340199421981. The reversal of 5340199421951 is 1591249910435.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5340199421951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5340199421893 and 5340199421902.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5340199421981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2670099710975 + 2670099710976.
It is an arithmetic number, because the mean of its divisors is an integer number (2670099710976).
Almost surely, 25340199421951 is an apocalyptic number.
5340199421951 is a deficient number, since it is larger than the sum of its proper divisors (1).
5340199421951 is an equidigital number, since it uses as much as digits as its factorization.
5340199421951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1749600, while the sum is 53.
The spelling of 5340199421951 in words is "five trillion, three hundred forty billion, one hundred ninety-nine million, four hundred twenty-one thousand, nine hundred fifty-one".
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