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5340199421981 is a prime number
BaseRepresentation
bin100110110110101110010…
…1100001000100000011101
3200220111222200100101012002
41031231130230020200131
51144443212023000411
615205130450452045
71060550056064504
oct115553454104035
920814880311162
105340199421981
11177984739a556
12722b71b94025
132c976a3895a8
1414667776783b
1593d9e15a33b
hex4db5cb0881d

5340199421981 has 2 divisors, whose sum is σ = 5340199421982. Its totient is φ = 5340199421980.

The previous prime is 5340199421951. The next prime is 5340199421983. The reversal of 5340199421981 is 1891249910435.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3375520633081 + 1964678788900 = 1837259^2 + 1401670^2 .

It is a cyclic number.

It is not a de Polignac number, because 5340199421981 - 222 = 5340195227677 is a prime.

It is a super-2 number, since 2×53401994219812 (a number of 26 digits) contains 22 as substring.

Together with 5340199421983, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5340199421983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2670099710990 + 2670099710991.

It is an arithmetic number, because the mean of its divisors is an integer number (2670099710991).

Almost surely, 25340199421981 is an apocalyptic number.

It is an amenable number.

5340199421981 is a deficient number, since it is larger than the sum of its proper divisors (1).

5340199421981 is an equidigital number, since it uses as much as digits as its factorization.

5340199421981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2799360, while the sum is 56.

The spelling of 5340199421981 in words is "five trillion, three hundred forty billion, one hundred ninety-nine million, four hundred twenty-one thousand, nine hundred eighty-one".