Base | Representation |
---|---|
bin | 100110110111001001001… |
… | …1111100110001000001111 |
3 | 200220121022120220102122022 |
4 | 1031232102133212020033 |
5 | 1200002034114330403 |
6 | 15205400214240355 |
7 | 1060611326546642 |
oct | 115562237461017 |
9 | 20817276812568 |
10 | 5341102105103 |
11 | 177a16a994766 |
12 | 7231843560bb |
13 | 2c98823b230b |
14 | 1467215c1a59 |
15 | 93e03516d38 |
hex | 4db927e620f |
5341102105103 has 4 divisors (see below), whose sum is σ = 5342620761480. Its totient is φ = 5339583448728.
The previous prime is 5341102105069. The next prime is 5341102105133. The reversal of 5341102105103 is 3015012011435.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5341102105103 - 212 = 5341102101007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5341102105133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 759322913 + ... + 759329946.
It is an arithmetic number, because the mean of its divisors is an integer number (1335655190370).
Almost surely, 25341102105103 is an apocalyptic number.
5341102105103 is a deficient number, since it is larger than the sum of its proper divisors (1518656377).
5341102105103 is a wasteful number, since it uses less digits than its factorization.
5341102105103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1518656376.
The product of its (nonzero) digits is 1800, while the sum is 26.
Adding to 5341102105103 its reverse (3015012011435), we get a palindrome (8356114116538).
The spelling of 5341102105103 in words is "five trillion, three hundred forty-one billion, one hundred two million, one hundred five thousand, one hundred three".
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