Base | Representation |
---|---|
bin | 100110110111100100000… |
… | …1001100111010100000111 |
3 | 200220200122022210200222100 |
4 | 1031233020021213110013 |
5 | 1200010410042444310 |
6 | 15210025413003143 |
7 | 1060642540311114 |
oct | 115571011472407 |
9 | 20820568720870 |
10 | 5342002312455 |
11 | 177a592048886 |
12 | 7233959234b3 |
13 | 2c9996a4c1a3 |
14 | 1467a8d9390b |
15 | 93e57584ec0 |
hex | 4dbc8267507 |
5342002312455 has 24 divisors (see below), whose sum is σ = 9746811238320. Its totient is φ = 2699116957440.
The previous prime is 5342002312393. The next prime is 5342002312501. The reversal of 5342002312455 is 5542132002435.
5342002312455 is a `hidden beast` number, since 534 + 20 + 0 + 2 + 31 + 24 + 55 = 666.
It is not a de Polignac number, because 5342002312455 - 215 = 5342002279687 is a prime.
It is a super-3 number, since 3×53420023124553 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3123977106 + ... + 3123978815.
It is an arithmetic number, because the mean of its divisors is an integer number (406117134930).
Almost surely, 25342002312455 is an apocalyptic number.
5342002312455 is a deficient number, since it is larger than the sum of its proper divisors (4404808925865).
5342002312455 is a wasteful number, since it uses less digits than its factorization.
5342002312455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6247955951 (or 6247955948 counting only the distinct ones).
The product of its (nonzero) digits is 144000, while the sum is 36.
The spelling of 5342002312455 in words is "five trillion, three hundred forty-two billion, two million, three hundred twelve thousand, four hundred fifty-five".
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