Base | Representation |
---|---|
bin | 110001110000010001… |
… | …011001001000001001 |
3 | 12002220011012111221210 |
4 | 301300101121020021 |
5 | 1333402320340423 |
6 | 40313044523333 |
7 | 3600606556512 |
oct | 616021311011 |
9 | 162804174853 |
10 | 53423215113 |
11 | 20725015254 |
12 | a42b3b0549 |
13 | 50650334b8 |
14 | 282b221a09 |
15 | 15ca185b93 |
hex | c70459209 |
53423215113 has 4 divisors (see below), whose sum is σ = 71230953488. Its totient is φ = 35615476740.
The previous prime is 53423215081. The next prime is 53423215117. The reversal of 53423215113 is 31151232435.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 53423215113 - 25 = 53423215081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53423215117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8903869183 + ... + 8903869188.
It is an arithmetic number, because the mean of its divisors is an integer number (17807738372).
Almost surely, 253423215113 is an apocalyptic number.
It is an amenable number.
53423215113 is a deficient number, since it is larger than the sum of its proper divisors (17807738375).
53423215113 is a wasteful number, since it uses less digits than its factorization.
53423215113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17807738374.
The product of its digits is 10800, while the sum is 30.
Adding to 53423215113 its reverse (31151232435), we get a palindrome (84574447548).
The spelling of 53423215113 in words is "fifty-three billion, four hundred twenty-three million, two hundred fifteen thousand, one hundred thirteen".
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