Base | Representation |
---|---|
bin | 11000010010110110110100… |
… | …01010100100101100010111 |
3 | 21000011022212201021001010021 |
4 | 30021123122022210230113 |
5 | 24000301300114314341 |
6 | 305342505405210011 |
7 | 14152535002342615 |
oct | 1411333212445427 |
9 | 230138781231107 |
10 | 53424463432471 |
11 | 1602820792004a |
12 | 5baa028860907 |
13 | 23a6b9cbab231 |
14 | d29a876966b5 |
15 | 629a5d7d19d1 |
hex | 3096da2a4b17 |
53424463432471 has 2 divisors, whose sum is σ = 53424463432472. Its totient is φ = 53424463432470.
The previous prime is 53424463432451. The next prime is 53424463432513. The reversal of 53424463432471 is 17423436442435.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53424463432471 - 211 = 53424463430423 is a prime.
It is a super-3 number, since 3×534244634324713 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53424463432411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26712231716235 + 26712231716236.
It is an arithmetic number, because the mean of its divisors is an integer number (26712231716236).
Almost surely, 253424463432471 is an apocalyptic number.
53424463432471 is a deficient number, since it is larger than the sum of its proper divisors (1).
53424463432471 is an equidigital number, since it uses as much as digits as its factorization.
53424463432471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 23224320, while the sum is 52.
The spelling of 53424463432471 in words is "fifty-three trillion, four hundred twenty-four billion, four hundred sixty-three million, four hundred thirty-two thousand, four hundred seventy-one".
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