Base | Representation |
---|---|
bin | 11000010011000100000000… |
… | …01110110000001110011011 |
3 | 21000012000011012120020002012 |
4 | 30021202000032300032123 |
5 | 24000410300343412220 |
6 | 305350040201300135 |
7 | 14153205324466544 |
oct | 1411420016601633 |
9 | 230160135506065 |
10 | 53431544513435 |
11 | 16030210a13a80 |
12 | 5bab48419464b |
13 | 23a775ac3257a |
14 | d2a159cbb4cb |
15 | 629d252b4ac5 |
hex | 3098803b039b |
53431544513435 has 8 divisors (see below), whose sum is σ = 69946749181296. Its totient is φ = 38859305100640.
The previous prime is 53431544513419. The next prime is 53431544513443.
53431544513435 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53431544513435 - 24 = 53431544513419 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 485741313704 + ... + 485741313813.
It is an arithmetic number, because the mean of its divisors is an integer number (8743343647662).
Almost surely, 253431544513435 is an apocalyptic number.
53431544513435 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53431544513435 is a deficient number, since it is larger than the sum of its proper divisors (16515204667861).
53431544513435 is a wasteful number, since it uses less digits than its factorization.
53431544513435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 971482627533.
The product of its digits is 12960000, while the sum is 50.
It can be divided in two parts, 5343154 and 4513435, that added together give a palindrome (9856589).
The spelling of 53431544513435 in words is "fifty-three trillion, four hundred thirty-one billion, five hundred forty-four million, five hundred thirteen thousand, four hundred thirty-five".
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