Base | Representation |
---|---|
bin | 110001110000110001… |
… | …001101000111100111 |
3 | 12002220201220012111021 |
4 | 301300301031013213 |
5 | 1333411434221120 |
6 | 40313543352011 |
7 | 3601040501632 |
oct | 616061150747 |
9 | 162821805437 |
10 | 53431554535 |
11 | 207297a0837 |
12 | a432152607 |
13 | 5066993278 |
14 | 282c392c19 |
15 | 15cac81aaa |
hex | c70c4d1e7 |
53431554535 has 4 divisors (see below), whose sum is σ = 64117865448. Its totient is φ = 42745243624.
The previous prime is 53431554509. The next prime is 53431554601. The reversal of 53431554535 is 53545513435.
53431554535 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53431554535 - 29 = 53431554023 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53431554491 and 53431554500.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5343155449 + ... + 5343155458.
It is an arithmetic number, because the mean of its divisors is an integer number (16029466362).
Almost surely, 253431554535 is an apocalyptic number.
53431554535 is a deficient number, since it is larger than the sum of its proper divisors (10686310913).
53431554535 is a wasteful number, since it uses less digits than its factorization.
53431554535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10686310912.
The product of its digits is 1350000, while the sum is 43.
The spelling of 53431554535 in words is "fifty-three billion, four hundred thirty-one million, five hundred fifty-four thousand, five hundred thirty-five".
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