Base | Representation |
---|---|
bin | 11000010011001001111111… |
… | …01000100111111011001011 |
3 | 21000012022110000001121111122 |
4 | 30021210333220213323023 |
5 | 24000433334432242220 |
6 | 305351330553145455 |
7 | 14153351026501253 |
oct | 1411447750477313 |
9 | 230168400047448 |
10 | 53434755743435 |
11 | 16031609637670 |
12 | 5bb001b6bb28b |
13 | 23a7b50303771 |
14 | d2a38258a963 |
15 | 629e62180425 |
hex | 30993fa27ecb |
53434755743435 has 8 divisors (see below), whose sum is σ = 69950952973296. Its totient is φ = 38861640540640.
The previous prime is 53434755743389. The next prime is 53434755743489.
53434755743435 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53434755743435 - 28 = 53434755743179 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 485770506704 + ... + 485770506813.
It is an arithmetic number, because the mean of its divisors is an integer number (8743869121662).
Almost surely, 253434755743435 is an apocalyptic number.
53434755743435 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53434755743435 is a deficient number, since it is larger than the sum of its proper divisors (16516197229861).
53434755743435 is a wasteful number, since it uses less digits than its factorization.
53434755743435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 971541013533.
The product of its digits is 635040000, while the sum is 62.
The spelling of 53434755743435 in words is "fifty-three trillion, four hundred thirty-four billion, seven hundred fifty-five million, seven hundred forty-three thousand, four hundred thirty-five".
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