Base | Representation |
---|---|
bin | 11000010011010011111101… |
… | …11010011001010011000101 |
3 | 21000012211021022102121101120 |
4 | 30021221332322121103011 |
5 | 24001030322224142041 |
6 | 305354014303344153 |
7 | 14153630541662400 |
oct | 1411517672312305 |
9 | 230184238377346 |
10 | 53440112334021 |
11 | 16033908260436 |
12 | 5bb10755b2059 |
13 | 23a84c4cb52aa |
14 | d2a72db52d37 |
15 | 62a177573366 |
hex | 309a7ee994c5 |
53440112334021 has 24 divisors (see below), whose sum is σ = 82887019588800. Its totient is φ = 30537091089792.
The previous prime is 53440112334019. The next prime is 53440112334031. The reversal of 53440112334021 is 12043321104435.
It is not a de Polignac number, because 53440112334021 - 21 = 53440112334019 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53440112334001) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 51562680 + ... + 52588878.
It is an arithmetic number, because the mean of its divisors is an integer number (3453625816200).
Almost surely, 253440112334021 is an apocalyptic number.
It is an amenable number.
53440112334021 is a deficient number, since it is larger than the sum of its proper divisors (29446907254779).
53440112334021 is a wasteful number, since it uses less digits than its factorization.
53440112334021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1380473 (or 1380466 counting only the distinct ones).
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 53440112334021 its reverse (12043321104435), we get a palindrome (65483433438456).
The spelling of 53440112334021 in words is "fifty-three trillion, four hundred forty billion, one hundred twelve million, three hundred thirty-four thousand, twenty-one".
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