Base | Representation |
---|---|
bin | 110001110001101100… |
… | …011010001001011001 |
3 | 12002221211002200201211 |
4 | 301301230122021121 |
5 | 1333424422340033 |
6 | 40315300143121 |
7 | 3601316431216 |
oct | 616154321131 |
9 | 162854080654 |
10 | 53447074393 |
11 | 20737531069 |
12 | a437397aa1 |
13 | 5069c6840b |
14 | 2830472b0d |
15 | 15cc2ea2cd |
hex | c71b1a259 |
53447074393 has 2 divisors, whose sum is σ = 53447074394. Its totient is φ = 53447074392.
The previous prime is 53447074391. The next prime is 53447074441. The reversal of 53447074393 is 39347074435.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 44027789584 + 9419284809 = 209828^2 + 97053^2 .
It is a cyclic number.
It is not a de Polignac number, because 53447074393 - 21 = 53447074391 is a prime.
It is a super-2 number, since 2×534470743932 (a number of 22 digits) contains 22 as substring.
Together with 53447074391, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (53447074391) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26723537196 + 26723537197.
It is an arithmetic number, because the mean of its divisors is an integer number (26723537197).
Almost surely, 253447074393 is an apocalyptic number.
It is an amenable number.
53447074393 is a deficient number, since it is larger than the sum of its proper divisors (1).
53447074393 is an equidigital number, since it uses as much as digits as its factorization.
53447074393 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3810240, while the sum is 49.
The spelling of 53447074393 in words is "fifty-three billion, four hundred forty-seven million, seventy-four thousand, three hundred ninety-three".
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