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53505025493 is a prime number
BaseRepresentation
bin110001110101001001…
…011110010111010101
312010002212010220200212
4301311021132113111
51334034241303433
640325130215205
73602622132653
oct616511362725
9163085126625
1053505025493
1120767212637
12a452884505
135078c788ca
142838039dd3
1515d2445d48
hexc7525e5d5

53505025493 has 2 divisors, whose sum is σ = 53505025494. Its totient is φ = 53505025492.

The previous prime is 53505025481. The next prime is 53505025529. The reversal of 53505025493 is 39452050535.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 45820399249 + 7684626244 = 214057^2 + 87662^2 .

It is a cyclic number.

It is not a de Polignac number, because 53505025493 - 28 = 53505025237 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53505025493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53505025403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26752512746 + 26752512747.

It is an arithmetic number, because the mean of its divisors is an integer number (26752512747).

Almost surely, 253505025493 is an apocalyptic number.

It is an amenable number.

53505025493 is a deficient number, since it is larger than the sum of its proper divisors (1).

53505025493 is an equidigital number, since it uses as much as digits as its factorization.

53505025493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 405000, while the sum is 41.

The spelling of 53505025493 in words is "fifty-three billion, five hundred five million, twenty-five thousand, four hundred ninety-three".