Base | Representation |
---|---|
bin | 100110111100010000010… |
… | …0100111110101001001111 |
3 | 200221122122100212200022211 |
4 | 1031320200210332221033 |
5 | 1200142022402044003 |
6 | 15214413143051251 |
7 | 1061450266546504 |
oct | 115704044765117 |
9 | 20848570780284 |
10 | 5352075815503 |
11 | 17838912a680a |
12 | 725327440b27 |
13 | 2ca910a33791 |
14 | 147082bab4ab |
15 | 94346b1196d |
hex | 4de2093ea4f |
5352075815503 has 2 divisors, whose sum is σ = 5352075815504. Its totient is φ = 5352075815502.
The previous prime is 5352075815497. The next prime is 5352075815509. The reversal of 5352075815503 is 3055185702535.
It is a balanced prime because it is at equal distance from previous prime (5352075815497) and next prime (5352075815509).
It is a cyclic number.
It is not a de Polignac number, because 5352075815503 - 233 = 5343485880911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5352075815509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2676037907751 + 2676037907752.
It is an arithmetic number, because the mean of its divisors is an integer number (2676037907752).
Almost surely, 25352075815503 is an apocalyptic number.
5352075815503 is a deficient number, since it is larger than the sum of its proper divisors (1).
5352075815503 is an equidigital number, since it uses as much as digits as its factorization.
5352075815503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3150000, while the sum is 49.
The spelling of 5352075815503 in words is "five trillion, three hundred fifty-two billion, seventy-five million, eight hundred fifteen thousand, five hundred three".
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