Base | Representation |
---|---|
bin | 100110111100111001011… |
… | …0010101001101110011111 |
3 | 200221210012111022012020101 |
4 | 1031321302302221232133 |
5 | 1200202334003202201 |
6 | 15215202054401531 |
7 | 1061526415544212 |
oct | 115716262515637 |
9 | 20853174265211 |
10 | 5353455131551 |
11 | 178442994832a |
12 | 7256513602a7 |
13 | 2caaa071c717 |
14 | 147174057779 |
15 | 943c7c6cd01 |
hex | 4de72ca9b9f |
5353455131551 has 2 divisors, whose sum is σ = 5353455131552. Its totient is φ = 5353455131550.
The previous prime is 5353455131533. The next prime is 5353455131569. The reversal of 5353455131551 is 1551315543535.
5353455131551 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (5353455131533) and next prime (5353455131569).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5353455131551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5353455131251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2676727565775 + 2676727565776.
It is an arithmetic number, because the mean of its divisors is an integer number (2676727565776).
Almost surely, 25353455131551 is an apocalyptic number.
5353455131551 is a deficient number, since it is larger than the sum of its proper divisors (1).
5353455131551 is an equidigital number, since it uses as much as digits as its factorization.
5353455131551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1687500, while the sum is 46.
The spelling of 5353455131551 in words is "five trillion, three hundred fifty-three billion, four hundred fifty-five million, one hundred thirty-one thousand, five hundred fifty-one".
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