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535347647141 is a prime number
BaseRepresentation
bin1111100101001010011…
…01001101001010100101
31220011211022001020101212
413302211031031022211
532232342444202031
61045534010001205
753451261630236
oct7624515151245
91804738036355
10535347647141
11197048876a1a
1287906a16205
133b6383b2a08
141bca798708d
15ddd3e8512b
hex7ca534d2a5

535347647141 has 2 divisors, whose sum is σ = 535347647142. Its totient is φ = 535347647140.

The previous prime is 535347647123. The next prime is 535347647143. The reversal of 535347647141 is 141746743535.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 519451732900 + 15895914241 = 720730^2 + 126079^2 .

It is a cyclic number.

It is not a de Polignac number, because 535347647141 - 218 = 535347384997 is a prime.

It is a Sophie Germain prime.

Together with 535347647143, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 535347647141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (535347647143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267673823570 + 267673823571.

It is an arithmetic number, because the mean of its divisors is an integer number (267673823571).

Almost surely, 2535347647141 is an apocalyptic number.

It is an amenable number.

535347647141 is a deficient number, since it is larger than the sum of its proper divisors (1).

535347647141 is an equidigital number, since it uses as much as digits as its factorization.

535347647141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4233600, while the sum is 50.

The spelling of 535347647141 in words is "five hundred thirty-five billion, three hundred forty-seven million, six hundred forty-seven thousand, one hundred forty-one".