Base | Representation |
---|---|
bin | 110001110111001111… |
… | …110011111101001111 |
3 | 12010012022102001121110 |
4 | 301313033303331033 |
5 | 1334122300204411 |
6 | 40332425103103 |
7 | 3603530353521 |
oct | 616717637517 |
9 | 163168361543 |
10 | 53540241231 |
11 | 20785085754 |
12 | a462627a93 |
13 | 5083358919 |
14 | 283c9a5a11 |
15 | 15d55a02a6 |
hex | c773f3f4f |
53540241231 has 4 divisors (see below), whose sum is σ = 71386988312. Its totient is φ = 35693494152.
The previous prime is 53540241217. The next prime is 53540241233. The reversal of 53540241231 is 13214204535.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 53540241231 - 217 = 53540110159 is a prime.
It is a super-2 number, since 2×535402412312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53540241233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8923373536 + ... + 8923373541.
It is an arithmetic number, because the mean of its divisors is an integer number (17846747078).
Almost surely, 253540241231 is an apocalyptic number.
53540241231 is a deficient number, since it is larger than the sum of its proper divisors (17846747081).
53540241231 is a wasteful number, since it uses less digits than its factorization.
53540241231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17846747080.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 53540241231 its reverse (13214204535), we get a palindrome (66754445766).
The spelling of 53540241231 in words is "fifty-three billion, five hundred forty million, two hundred forty-one thousand, two hundred thirty-one".
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