Base | Representation |
---|---|
bin | 11000010110010010100010… |
… | …00100011010101111010111 |
3 | 21000120121100110220201002012 |
4 | 30023021101010122233113 |
5 | 24004214340120041120 |
6 | 305513014351534435 |
7 | 14164212066256562 |
oct | 1413112104325727 |
9 | 230517313821065 |
10 | 53542422424535 |
11 | 16073239679750 |
12 | 6008a68b2a41b |
13 | 23b504b2909a5 |
14 | d3167790b4d9 |
15 | 62cb644c41c5 |
hex | 30b25111abd7 |
53542422424535 has 16 divisors (see below), whose sum is σ = 70092276262272. Its totient is φ = 38939733684000.
The previous prime is 53542422424523. The next prime is 53542422424541.
53542422424535 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53542422424535 - 224 = 53542405647319 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8064860 + ... + 13119710.
It is an arithmetic number, because the mean of its divisors is an integer number (4380767266392).
Almost surely, 253542422424535 is an apocalyptic number.
53542422424535 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53542422424535 is a deficient number, since it is larger than the sum of its proper divisors (16549853837737).
53542422424535 is a wasteful number, since it uses less digits than its factorization.
53542422424535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5247454.
The product of its digits is 23040000, while the sum is 50.
It can be divided in two parts, 5354242 and 2424535, that added together give a palindrome (7778777).
The spelling of 53542422424535 in words is "fifty-three trillion, five hundred forty-two billion, four hundred twenty-two million, four hundred twenty-four thousand, five hundred thirty-five".
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