Base | Representation |
---|---|
bin | 100110111101010110001… |
… | …0011110011110101111111 |
3 | 200221212200202002221110112 |
4 | 1031322230103303311333 |
5 | 1200211323023000210 |
6 | 15215441525500235 |
7 | 1061562344055311 |
oct | 115725423636577 |
9 | 20855622087415 |
10 | 5354420125055 |
11 | 1784884631221 |
12 | 72588057167b |
13 | 2cabc5620bb1 |
14 | 1472262917b1 |
15 | 94432836d05 |
hex | 4deac4f3d7f |
5354420125055 has 8 divisors (see below), whose sum is σ = 6428409674400. Its totient is φ = 4281465750496.
The previous prime is 5354420125037. The next prime is 5354420125079. The reversal of 5354420125055 is 5505210244535.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5354420125055 is a prime.
It is a super-4 number, since 4×53544201250554 (a number of 52 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 258782315 + ... + 258803004.
It is an arithmetic number, because the mean of its divisors is an integer number (803551209300).
Almost surely, 25354420125055 is an apocalyptic number.
5354420125055 is a deficient number, since it is larger than the sum of its proper divisors (1073989549345).
5354420125055 is a wasteful number, since it uses less digits than its factorization.
5354420125055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 517587393.
The product of its (nonzero) digits is 600000, while the sum is 41.
The spelling of 5354420125055 in words is "five trillion, three hundred fifty-four billion, four hundred twenty million, one hundred twenty-five thousand, fifty-five".
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