Base | Representation |
---|---|
bin | 100110111101110011100… |
… | …0010100000010011001101 |
3 | 200221222020102011100100221 |
4 | 1031323213002200103031 |
5 | 1200220332243204201 |
6 | 15220123404351341 |
7 | 1061625640123213 |
oct | 115734702402315 |
9 | 20858212140327 |
10 | 5355405444301 |
11 | 178523a838150 |
12 | 725ab6545551 |
13 | 2cb0217bab33 |
14 | 1472bb09acb3 |
15 | 9448e0b84a1 |
hex | 4dee70a04cd |
5355405444301 has 4 divisors (see below), whose sum is σ = 5842260484704. Its totient is φ = 4868550403900.
The previous prime is 5355405444283. The next prime is 5355405444331. The reversal of 5355405444301 is 1034445045535.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5355405444301 - 25 = 5355405444269 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5355405444331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 243427520185 + ... + 243427520206.
It is an arithmetic number, because the mean of its divisors is an integer number (1460565121176).
Almost surely, 25355405444301 is an apocalyptic number.
It is an amenable number.
5355405444301 is a deficient number, since it is larger than the sum of its proper divisors (486855040403).
5355405444301 is a wasteful number, since it uses less digits than its factorization.
5355405444301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 486855040402.
The product of its (nonzero) digits is 1440000, while the sum is 43.
The spelling of 5355405444301 in words is "five trillion, three hundred fifty-five billion, four hundred five million, four hundred forty-four thousand, three hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •