53613403 has 2 divisors, whose sum is σ = 53613404. Its totient is φ = 53613402.

The previous prime is 53613401. The next prime is 53613409. The reversal of 53613403 is 30431635.

53613403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 53613403 - 2¹ = 53613401 is a prime.

Together with 53613401, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (53613401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26806701 + 26806702.

It is an arithmetic number, because the mean of its divisors is an integer number (26806702).

Almost surely, 2^53613403 is an apocalyptic number.

53613403 is a deficient number, since it is larger than the sum of its proper divisors (1).

53613403 is an equidigital number, since it uses as much as digits as its factorization.

53613403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 25.

The square root of 53613403 is about 7322.1173850192. The cubic root of 53613403 is about 377.0721506799.

The spelling of 53613403 in words is "fifty-three million, six hundred thirteen thousand, four hundred three".